A drive for the
system to crush coal and deliver it by conveyers to a rail car is shown below;
gear A deliver 15KW to the crusher and Gear E delivers 7.5Kw to conveyers or,
all power enters through Gear C. The shaft carrying Gear A, C, and E rotates at
480rpm, the distances from the middle of each bearing to the middle of the face
of the nearest gear is 100m. Design Shaft Diameters.
Solution
Given Data:
Gear A power deliver to crusher =
15KW
Gear E delivers to conveys = 7.5KW
Speed = 480rpm
Distance = 100m
Power at gear C = power to crusher
(15KW); + power to conveyer (7.5KW)
22.5KW = 22.5
N.m/s
Supposed:
= 3.0 for all shaft diameters
= 0.81 for 0.99 reliability
= 0.80
N= 4; due to impact and shook of
coal crusher
= 400MPa
To Find:
Calculate the minimum diameters
for Shaft 1
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From problem 1, after calculating the minimum diameters for the shaft,
let’s specify the following dimensions for design of shaft.
Mating
part
|
Diameter
number
|
Minimum
diameters
|
Specified
shaft diameters
|
Gear
A
|
|
= 58.34mm
|
50mm
|
Nothing
|
|
= 68.61534mm
|
60mm
|
Bearing
B
|
|
= 68.61534mm
|
65mm
|
Gera
C
|
|
= 64.68mm
|
80mm
|
Bearing
D
|
|
= 60.94mm
|
60mm
|
Nothing
|
|
= 60.94mm
|
55mm
|
Gear
E
|
|
= 62.92mm
|
45mm
|
Specify suitable single row, deep grove ball bearings
from Table 14-3 for the shaft of examples 12-3 use the data which is solved in
above examples;
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