Data of Quality/Graph: 1). For below equation, calculate the angle which will give you maximum range for initial height and velocity?

Now the Calculated angle is not equal to the 45 because height is not equal to zero, when height is equal to zero the angle occurs at 45.

Data Table 1:

Initial Speed of Projectiles:

Distance = 10cm

Initial speed = 409.1

Table 2: Range:

Angle 1:

Launcher angle = 25

Launcher Height = 117cm

Angle 2:

Launcher angle = 45

Launcher Height = 117.5cm

Graph between Angle and Range of Projectile motion:  

Graph between Height and Range of Projectile motion: 

Assigned Question

2. Show the expression that you obtained for the range of they projectile, Equation (4-1) reduces to a simpler expression, when h=0; i.e. when the projectile is fired and lands at the same height.

Use the equation of motion calculate the time reach to height

Show the expression derive form 7-1

Calculate the maximum height;

Is the range R different if a horizontal wind is blowing in the same direction as the balls displacements? If so is the range greater or less than it would be without the wind? Why?

Yes, range is different in the horizontal wind, as the ball displacements are same. And the range is greater without the wind. Because as we know that

Analysis

A1. Calculate the initial speeds.

S=vt

From P1 the s= 10cm and the t = 0.0244

Error % is shown in 1^st table

A 2.

Initial speed = 40.9m/s

Initial height = 117cm= 1.17m

Initial angle = 25

                                                                                                                     g= 9.81m/s²