Light scattering data was collected for four different protein concentrations (.38 mg/ml, .54 mg/ml, .69 mg/ml and .79 mg /ml) and five different angles (q2kc) listed below. Based on the results as listed, calculate the average molecular weight and the radius of gyration for this protein

Formula for average molecular weight

Where

K=1.

Question 2

Based on the attached paper, derive a mathematical equation that relates the peak elution volume to the dissociation constant for a rapidly exchanging dimer.  The formula should be a function of the mole fraction monomer (m), mole fraction dimer (d) and the total amount of protein loaded.  You must show all work and all steps of the derivation.

The dissociation factor can be calculated with the help of weight averaged molar mass.

A system will be define as where this protein is dimerising can be explained as

Where this M represent the monomer and D represent the dimer so from where we can easily find the equilibrium dissociation constant

   This is because without extinction coefficient it is impossible to calculate the concentration. The reason is that the extinction coefficient is based on concentration factor

Where the  is the extinction coefficient so according to that equation when the =0 so the concentration of protein is equal to infinity.

Question 4

Based on the data supplied, calculate number average; weight average and z-average molecular weights from the SEC data.  Assume the extinction coefficient (25000 M^-1cm^-1) is equivalent for all samples.

Formula for