
As
the interest rate of 5 years is 1.2 times of the annual effective rate for 10
years, it can be written as
Taking
1/5 of whole equation

Solving
the equation gives

(2) The present value
of a payment 1004 at time t-month from now is the sum of the present values of
the following payments: (a) 500 at the end of 4 months, (b) 400 at the end of
10 months, and (c) 100 at the end of 16 months.
Determine t if the annual effective interest is 5%.
Solution
Present Value Formula is below ;
Effective
interest rate is 5%

(3) Brian has $1,000 to invest at time 0 and
two ways to invest it.
Investment
option (A): it provides the force of interest at 1.08/(1+0.08) at time t.
Investment
option (B): it provides a 5% annual effective interest rate.
Brian
can invest any portion of his money in either (A) or (B), and can transfer any
portion of his money between the two investments at any time. What is the
maximum amount Brian can accumulate at t =15.
(Hint: option (A) is better in the early years but worse is the later
years, so you need to find the cross over time first).
Solution
When investing money you
want to apply the largest force of interest possible to your money. The force
of interest is given for investment A. We need to convert to a force of interest
for investment B. Since the effective rates does not vary for investment B the
force of interest is constant and equal to ln(1.05)which is approximately equal
to 0.04879. Therefore as long as the force of interest for investment A is
greater than 0.4879 then we invest in A.

We find that t<1
So, we invest in A for 8
years and then B for the remaining 12 years
By inspection we see that,
A (t) = 1+0.08t, so that accumulated
value at time 15 is;
1000(1+0.08times3) + ({1.05}12
Approx, $1241.79 max
amount of return
4).
) Fund X pays nominal interest rate of 6% convertible monthly, (ii) Fund Y pays
interest at a force of interest of 1/(t+12).
Jill deposits same amount of money into each fund now, at the end of 12
years, the accumulated amount of fund X is 1,000. Determine the accumulated amount of fund Y.
Solution
For
Y
Interest
rate = 6% monthly Convertible
Effective
interest rates = (1+0.06/12))^12-1
=5.8%
i.e
Effective annual interest rates = 6.16%
Now
principle = P
Compound
Sum = F = 1000
So,
F= P* (1+0.0616)^12 = P*2.0489

a(12) = 1551.08