Sample | The proportion of
defective item | Total Defective
Proportions |
1 | 0.01 | 0.21 |
2 | 0.03 | |
3 | 0 | |
4 | 0.04 | |
5 | 0.01 | |
6 | 0.01 | |
7 | 0 | |
8 | 0.01 | |
9 | 0.02 | |
10 | 0.02 | |
11 | 0.03 | |
12 | 0.03 | |
Particulars
|
Formulas
|
Calculations
|
Sample Taken
|
99
|
|
Mean of Proportionate
defective
|
m
|
|
Standard Deviation
|
Sigma
|
|
Mean of Proportionate
defective
|
Total defective
Proportions/number of samples
|
0.0175
|
Standard Deviation
(Sigma)
|
STDEV.S function in
excel
|
0.0129
|
Upper Control Limit
|
m+3*Sigma
|
0.056
|
Lower Control Limit
|
m-3*upper limit
|
-0.151
|
The
mean of Proportionate defective is calculated by using the arithmetic mean
formula, which is mentioned as follows:
The
mean in the above table is denoted with m. In the first step, the sum of all
the proportion of defective items is calculated that is 0.21. After calculating
total defective proportions the mean of the proportionate defective is
evaluated by dividing the total with the number of samples. The mean of
proportionate defective is 0.0175.
For evaluating the UCL
& LCL first standard deviation is calculated. The formula of standard
deviation is:
When
the standard deviation is calculated, the UCL and LCL can be calculated. In the
above table, it can be seen that the UCL is 0.056 and LCL is -0.151 (Anderson, Sweeney, & Williams, 2010).
a. Draw a control chart and plot each of
the sample measurements on it?
The sample measures, which
include upper limit, lower limit and mean of the proportionate defective are
done in order to know the statistical control. In the above control chart the proportionate
defective is plotted, which can be seen in the chart as blue line. The upper
control limit in the chart can be seen with the orange dot above the blue line
with a value of 0.056. The lower control limit can be seen with the grey dot
below the blue line having a value of -0.151 (Brown & Bessant, 2013).
b. Does it appear
that the process for making tees is in statistical control?
From the control chart above, it
can be seen that the proportion of defective items is within the control
limits. In the process of making tees, no control limit has been breached,
which is evident from the chart above. Therefore it can be said that the
process of making tees is in statistical control. If the blue line which is
indicating the proportion of defective items was above or below the UCL &
LCL than it can be said that the process is not in statistical control
(Wegner, 2010).
Question
No. 2
a.
Forecast the demand for week 7 using
a five-period moving average?
Week
|
Demand
|
5 year moving Average
|
1
|
649
|
|
2
|
524
|
|
3
|
561
|
|
4
|
738
|
|
5
|
511
|
|
6
|
600
|
596.6
|
7
|
|
586.8
|
The moving average is calculated
with the formula:
By using a 5-year moving average
the demand for week seven is forecasted. In week 7 it is forecasted that the
demand will be 586.8 (Mahadevan, 2009).
b.
Forecast the demand for week 7 using a three-period weighted moving
average.
Week
|
Demand
|
3 year weighted moving
Average
|
1
|
649
|
|
2
|
524
|
|
3
|
561
|
|
4
|
738
|
567.50
|
5
|
511
|
642.10
|
6
|
600
|
589.10
|
7
|
|
600.90
|
The weighted moving average is
calculated with the formula, which is mentioned as follows:
By using 3 years weighted moving
average the demand for week seven is forecasted. In week 7 it is forecasted
that the demand will be 600.90 (Anderson, Sweeney, & Williams, 2010).
c.
Forecast the demand for week 7 using exponential smoothing. Use an
α value of .1 and assume the forecast for week 6 was 602 units?
Week
|
Demand
|
3 year moving Average
|
1
|
649
|
|
2
|
524
|
649
|
3
|
561
|
637
|
4
|
738
|
629
|
5
|
511
|
640
|
6
|
600
|
602
|
7
|
|
601.8
|
The demand for week 7 is
calculated by using exponential smoothing. The formula of exponential smoothing
is mentioned as follows:
It is forecasted that the demand
for week 6 will be 602. Therefore with the exponential smoothing method, the
demand in week 7 will be 601.8.
d.
What assumptions are made in each of the above forecasts?
The main assumption in the moving
average model and the exponential smoothing model is the time series, which
remains stationary and have slow-changing mean. Therefore the moving average is
used for evaluating the current mean which is then utilized for forecasting the
future. The exponential smoothing technique can be described as the weighted
average approach. This technique is usually used for short term forecasting,
and that data which is used in this technique is historical (Anderson, Sweeney, & Williams, 2010).
References of Assignment Determine the mean proportion defective, the UCL, and the LCL?
Anderson, Sweeney, D. J., & Williams, T. A.
(2010). Fundamentals of Business Statistics (illustrated ed.). Cengage
Learning.
Brown, S., & Bessant, J. (2013). Strategic Operations
Management. Routledge.
Mahadevan, B. (2009). Operation Management: Theory and
Practice. Pearson Education, India.
Wegner, T. (2010). Applied Business Statistics: Methods
and Excel-based Applications (illustrated ed.). Juta and Company Ltd.