Problem 1
If resting membrane potential of a cardiac cell is -90mV, the concentration of K^+ outside the cell is 5mM and membrane permeability for all cations (except forK^+) is zero. What is the concentration of K^+ inside of the cell?
Answer:
Given data;
Resting membrane potential of a cardiac cell =-90mV
Concentration of K^+ outside the cell = 5mM
Concentration of K^+ inside of the cell?
E_(m,K^+ )=RT/F ln([K^+ ]_out/[K^+ ]_in
E_(m,K^+ )=61.5mVln([K^+ ]_out/[K^+ ]_in
-90mV=61.5mV ln([5mM]_out/[K^+ ]_in
(-90mV)/(61.5mV.)=ln [5mM]_out/[K^+ ]_in
1.46mV=ln [5mM]_out/[K^+ ]_in
0.3784=[5mM]_out/[K^+ ]_in
[K^+ ]_in=[5mM]_out/0.3784
[K^+ ]_in=13.21mM
Concentration of K^+ inside the cell = 13.21mM
Problem 2
The internal concentration of K^+ in a cell is 150mM, and the cell’s diameter is 10μm. If resting membrane potential of the cell is -50mV, and the capacitance of the cell membrane is 0.5 μF/cm2, what is the surface density of K^+ needed to produce the resting membrane potential? (HINT: Wikipedia has a good explanation and definition of capacitance.)
Solution
Internal concentration of K^+ in a cell = 150mM
Cell’s diameter =10μm=0.5×10^(-6)
Membrane potential of the cell is = -50mV
Capacitance of the cell membrane = 0.5 μF/cm^2 =0.5×10^2 F/m^2
What is the surface density of K^+= ?
Charge density is σ=cv= -0.5×0.5×10^(-2) c/m^2
Charge density is σ=0.25×10^(-2) c/m^2
σ_max=2.5×10^(-4) c/m^2
σ_(K^+ )= 2.5×10^(-4) c/m^2 ×150×10^(-3) c/m^2
σ_(K^+ )= 3.75×〖10〗^(-5) c/m^2