a) The linear
system has a unique
solution.
Solution
For proving it there is a need to take
determinant. But for that make it into coefficient form. It will become like
this
Now for taking determinant
This means that the determinant of this
matrix is not zero. This shows that the linear system is contain a unique
solution. It shows that it is true.
Solution
For proving this let consider the two
matrix A and B. the dimension of these
matrixes are
According to the given problem it can be not
these matrixes are
Now performing
It will get
Now work for
It will become like this
Now perform
Work for the left hand side
The answer will be
Its shows that it is a false statement
a) If
is an
nonsingular matrix, then
is
also nonsingular matrix.
For that case, there is need to prove it
Let consider the Matrix A
This will be
proved easily by taking determinant
Now in the first
step, there subtract row 1 from 3 it will become like this
Now work for the
second column. For this case subtract row 4 from row 2. Then after this multiply
row 2 by 2 and then subtract row 4 from 2. It will become like this
Now just subtract
row 4 from row three it will become like this
Now just multiply
the diagonal elements it will become like this
Hence proved left
hand side = right hand side
This shows it is a
true statement
a) If
are
distinct vectors in
and
is an
matrix such
that
, then
is invertible.
Solution
For
this purpose, there is need to show trivial solution
It
will show that
Now just factoring out the A
matrix it will become like this
Now the next thing is that
just suppose
It shows that A is
invertible, that implies only one solution and it is only when
this
will give the only solution to the given problem. According to this the
equation will become. Now it will become like this
It means A is completely
invertible
This statement is also true.
Q−2: Show that if
is a
matrix, then the only solution to
is the
zero matrix.
For proving this, there is need to suppose a matrix
of
The matrix
A will be about