A
food factory produces a cylindrical confectionary product of variable length,
depending on the required product size
Table
1: Replicate values of the diameter of product
Test
|
1
|
2
|
3
|
4
|
5
|
6
|
7
|
8
|
9
|
Diameter(mm)
|
9.1
|
9.9
|
10.1
|
10.9
|
9.2
|
10.9
|
10.8
|
9.3
|
10.2
|
Table 2: Variation of product mass a
function of length
Length (mm)
|
300
|
330
|
360
|
390
|
420
|
450
|
480
|
520
|
540
|
570
|
600
|
630
|
660
|
720
|
750
|
Mass (g)
|
23.2
|
27.4
|
29.1
|
30.6
|
34.2
|
38.3
|
40.5
|
42.2
|
52.5
|
50.4
|
55.2
|
52.2
|
53.5
|
64.1
|
65.4
|
Approximate
density of the extruded material based on the value
Expanded
uncertainty in density estimation, based on diameter and mass uncertainties
using 9% of confidence interval
Solution
The
density of the material is;
But in this case, we know that δ = 0.1mm. The
uncertainty is type B.
Since
this could either be +ve or –ve, the
most likely value is Z = 0.
Length versus mass
Now the residual plot is
Conclusion
Summing up all the discussion it is concluded
that the problem statement is about the uncertainty which is used the GUM
method. In this statement first of all determine the density of the extruded material,
and find its expanded uncertainty by using the GUM methods which is also shown
in the above calculation. Then plot the length versus mass . Moreover,
the discussion also concluded length and mass are increasing from the starting
point of above 250 (20 for mass) to the 750 (65 for mass). Although, the
calculated values of veff is 8.29 which represent the
combined uncertainty. However, opposite to this value, the calculated value of
standard uncertainty is 0.02. Thus discussion and calculation represent that
standard uncertainty is below the value of combined uncertainty. Furthermore,
the density of the material is also calculated to find out the final value of
extruded materials. The calculations concluded that the density of the material
is limited to the p-value of 0.001077 for the materials.