11/28/2017 Section 10.3
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3. –/2 pointsLarCalc10 10.3.012.
Find and find the slope and concavity (if possible) at the given value of the parameter. (If an answer does not exist, enter DNE.)
Parametric Equations Point
t = 2
concavity: Select
4. 2/2 points | Previous AnswersLarCalc10 10.3.017.
Find an equation of the tangent line at each given point on the curve.
dy/dx and d2y/dx2,
x = , y = t t − 1
= √t√t−1
=
slope
dy dx
d2y dx2
x = t2 − 4, y = t2 − 2t
at (0, 0) y=x2
at (−3, −1) y=−1
at (−3, 3) y=2x+9
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11/28/2017 Section 9.10
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4. 2/3 points | Previous AnswersLarCalc10 9.10.063.
Use a power series to approximate the value of the integral with an error of less than 0.0001. (Round your answer to four decimal places.)
(−1)n(8n+1)n!
= 0.9127
5. 0/1 points | Previous AnswersLarCalc10 9.10.007.
Use the definition of Taylor series to find the Taylor series (centered at c) for the function.
e−x8 dx 1
0
≈ e−x8 dx 1
0
7 Use the fewest number of terms.
n = 0
f(x) = ln(x), c = 1
f(x) =
(−1)n+1(x−1)nn
∞
n = 0
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11/28/2017 Section 9.8
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9. 0/2 points | Previous AnswersLarCalc10 9.8.038.
Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval. Enter your answer using interval notation.)
(0,2c)
2 ≤ x ≤ 4
x = 3
2 ≤ x < 4
2 < x ≤ 3
−∞ < x < ∞
∞
n = 1
(−1)n + 1(x − c)n
ncn
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