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how many mmoles in a mole
how many mmoles of oxalate, C2O4^2- ?
Mass of sample - What was the initial mass of the weighing paper in Trial #1? 0.2000 g Previous Answers ✓ Correct Part B Mass
Titration volume of KMnO4 - What was your initial reading in Trial #1? 0.51 ml Submit Previous Answers ✓ Correct Part E Titra
Calculations - how many mMoles of oxalate, C202 in Trial #1? 1Η ΑΣΦ + + Ο ΕΞ) ? mmol
mmol Na2C204 = 0.20 gx 1 mol 109 mmol - = 1.5 mmol 134.0 g 1 mol The reaction requires 2/5 mmol KMnO4 for each mmol Na C204.
Mass of sample - What was the initial mass of the weighing paper in Trial #1? 0.2000 g Previous Answers ✓ Correct Part B Mass of sample - What was the final mass of the weighing paper and sample in Trial #12 0.3000 g Previous Answers ✓ Correct Part C Mass of sample - What is the mass of the sample in Trial #12 0 1100 g
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Calculations - how many mMoles of oxalate, C202 in Trial #1? 1Η ΑΣΦ + + Ο ΕΞ) ? mmol
mmol Na2C204 = 0.20 gx 1 mol 109 mmol - = 1.5 mmol 134.0 g 1 mol The reaction requires 2/5 mmol KMnO4 for each mmol Na C204. If a 0.020 M KMnO4 solution is used, the number of mL required in a titration is (see Equa- tions [4] and [5]) mol) = V ml 0.020 mmol/mL Vm= 30 mL
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