Latent heat of fusion of water value

We did the lab of latent heat of fusion of ice, and I am confused that what the 'water equivalent' represents.

I thought it is the amount (kg) of water, but it is mccc according to this lab manual, which unit is (J/oC).

Please answer what the water equivalent represents and the unit of it.

- In this experiment, an ice cube of mass mt, assumed to be at 0°C, is placed in a calorimeter containing a mass of water rnw

In order to calculate the heat of fusion of ice from (3), it is necessary to first determine the water equivalent of the calo

- In this experiment, an ice cube of mass mt, assumed to be at 0°C, is placed in a calorimeter containing a mass of water rnw. at temperature T], . After the ice cube melts, the temperature of the system is T2. When the heat lost is equated to the heat gained, and the resulting equation solved for the latent heat of fusion L, the result is сс where cw is the specific heat of water (4.19 J/g °C) and mccc, is the water equivalent of the calorimeter 3-1
In order to calculate the heat of fusion of ice from (3), it is necessary to first determine the water equivalent of the calorimeter. The value mocc is found by mixing known quantities of warm water and cool water in the calorimeter Suppose the Calorimeter contains a mass of warm water mww, at temperature Tw. If a mass of ool water mcw, at temperature Tc is mixed with the warm water in the calorimeter. thermal equilibrium will be established at an intermediate temperature T When the heat lost and the heat gained are equated, and the resulting equation solved for the water equivalent of the calorimeter. the expression becomes T-T where cw is the specific heat of water.