Management cases peter drucker pdf

(1) A linear trend equation. (Round your intermediate calculations and final answer to 2 decimal places.)

Yt 20.86 ± 0.10 thousands

(2) A five­month moving average.

Moving average 19 thousands

(3) Exponential smoothing with a smoothing constant equal to .20, assuming a March forecast of 19(000). (Round your intermediate calculations and final answer to 2 decimal places.)

Forecast 19.26 ± 0.10 thousands

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2. Award: 25 out of 25.00 points

(4) The naive approach.

Naive approach 20 thousands

(5) A weighted average using .60 for August, .30 for July, and .10 for June. (Round your answer to 2 decimal places.)

Weighted average 20.40 ± 0.01 thousands

Explanation:

b. (1)

t Y tY 1 19 19 2 18 36 3 15 45 4 20 80 5 18 90 6 22 132 7 20 140 28 132 542

with n = 7, Σt = 28, Σt2 = 140

b = nΣty − ΣtΣy

= 7(542) − 28(132)

= .50 nΣt2 − (Σt)2 7(140) − 28(28)

a = Σy − bΣt

= 132 − .50(28)

= 16.86 n 7

For Sept., t = 8, and Yt = 16.86 + .50(8) = 20.86 (000)

(2) MA5 =

15 + 20 + 18 + 22 + 20 = 195

(3) Month Forecast = F(old) + .20 [Actual − F(Old)] April 18.8 = 19 + .20 [18 − 19] May 18.04 = 18.8 + .20 [15 − 18.8] June 18.43 = 18.04 + .20 [20 − 18.04] July 18.34 = 18.43 + .20 [18 − 18.43] August 19.07 = 18.34 + .20 [22 − 18.34] September 19.26 = 19.07 + .20 [20 − 19.07]

(5) .60(20) + .30(22) + .10(18) = 20.40

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Problem 3-3

A dry cleaner uses exponential smoothing to forecast equipment usage at its main plant. August usage was forecasted to be 88 percent of capacity; actual usage was 89.6 percent of capacity. A smoothing constant of .1 is used. a. Prepare a forecast for September. (Round your answer to 2 decimal places.)

Forecast for September 88.16 percent of capacity b. Assuming actual September usage of 92 percent, prepare a forecast for October usage.(Round your

answer to 2 decimal places.)

Forecast for October 88.54 percent of capacity

References

Worksheet Problem 3­3 Learning Objective: 03­10 Prepare an exponential smoothing forecast.

Problem 3-3

A dry cleaner uses exponential smoothing to forecast equipment usage at its main plant. August usage was forecasted to be 88 percent of capacity; actual usage was 89.6 percent of capacity. A smoothing constant of .1 is used. a. Prepare a forecast for September. (Round your answer to 2 decimal places.)

Forecast for September 88.16 ± 0.05 percent of capacity b. Assuming actual September usage of 92 percent, prepare a forecast for October usage.(Round your

answer to 2 decimal places.)

Forecast for October 88.54 ± 0.05 percent of capacity

Explanation:

a. 88 + .1(89.6 − 88) = 88.16

b. 88.16 + .1(92 − 88.16) = 88.54

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3. Award: 25 out of 25.00 points

Problem 3-4

An electrical contractor's records during the last five weeks indicate the number of job requests: Week: 1 2 3 4 5 Requests: 20 22 18 21 22 Predict the number of requests for week 6 using each of these methods: a. Naive.

Number of requests 22 b. A four­period moving average. (Round your answer to 2 decimal places.)

Number of requests 20.75

c. Exponential smoothing with α = .30. Use 20 for week 2 forecast. (Round your intermediate

calculations and final answers to 2 decimal places.)

Number of Requests F3 20.6 F4 19.82 F5 20.17 F6 20.72

References

Worksheet Learning Objective: 03­07 Use a naive method to make a forecast.

Learning Objective: 03­10 Prepare an exponential smoothing forecast.

Problem 3­4 Learning Objective: 03­08 Prepare a moving average forecast.

Problem 3-4

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4. Award: 25 out of 25.00 points

An electrical contractor's records during the last five weeks indicate the number of job requests: Week: 1 2 3 4 5 Requests: 20 22 18 21 22 Predict the number of requests for week 6 using each of these methods: a. Naive.

Number of requests 22 b. A four­period moving average. (Round your answer to 2 decimal places.)

Number of requests 20.75 ± 0.01

c. Exponential smoothing with α = .30. Use 20 for week 2 forecast. (Round your intermediate

calculations and final answers to 2 decimal places.)

Number of Requests F3 20.6 ± 0.05 F4 19.82 ± 0.05 F5 20.17 ± 0.05 F6 20.72 ± 0.05

Explanation:

b. 22 + 18 + 21 + 22 = 20.754

c. F3 = 20 + .30(22 − 20) = 20.6 F4 = 20.6 + .30(18 − 20.6) = 19.82 F5 = 19.82 + .30(21 − 19.82) = 20.17 F6 = 20.17 + .30(22 − 20.17) = 20.72

Problem 3-32

A manager has just received an evaluation from an analyst on two potential forecasting alternatives. The analyst is indifferent between the two alternatives, saying that they should be equally effective. Period: 1 2 3 4 5 6 7 8 9 10 Data: 37 39 37 39 45 49 47 49 51 54 Alt. 1: 36 38 40 42 46 46 46 48 52 55 Alt. 2: 36 37 38 38 41 52 47 48 52 53

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