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2s 1 x 5 (s - 3)(s + 4) Step 3 Partial fraction decomposition can now be used to write L{y}, such that all terms have linear denominators, which is required to move forward. А B + 2s - 5 (s - 3)(8 + 4) S 3 S + 4 = 2s - 5 Als + 4) + B(5 - 3) Now, solve for A and B by utilizing the real roots of the denominator, 3 and - 4. Doing so gives the following results. 1/6 x A = 17/6 X B = 7 Therefore, we have the following. 2s - 5 (s - 3)(s + 4) А S - 3 + B S + 4 1/6 X 17/6 x + 7 7 s 3 S + 4 Submit Skip (you cannot come back)
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