Velocity squared equation

Answer the questions, using complete sentences. When you have finished, submit this assignment to your teacher by the due date for full credit.

Motion in Two Dimensions 1

(5 points)

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1. Is the relationship between velocity and centripetal force a direct, linear relationship or is it a nonlinear square relationship? Explain the answer using your graphs of Fc vs. v and Fc vs.v2. What is the precise mathematical relationship between velocity and centripetal force?

Answer:

The relationship between velocity and centripetal force is a nonlinear square relationship. When we are referring to a graph a straight line would be said to be linear. Looking at our graph we can see that it’s not a straight line thus we know it’s a non linear relationship.

And we know From the formula that the relationship between centripetal force and velocity is that Centripetal Force is directly proportional to velocity squared and that gives us our precise mathematical relationship between the both .

(4 points)

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2. [img width="67" height="36" src="file:///C:/Users/Spare/AppData/Local/Temp/msohtmlclip1/01/clip_image002.gif" v:shapes="_x0000_s1026">y = mx, to the equation , and explain what the slope of the graph of Fc vs. v2 represents. Remember that the m in the equation for a line represents the slope, and the m in the centripetal force equation
represents the mass of the stopper.

Answer: Our equation shows us that Centripetal Force the and the square of velocity have a direct proportion

Which means as one is increased the other increases as well considering r in that case is constant.

This is verified by our centripetal force vs velocity square graph where as we plot the points we can see this direct relationship between the points and the graph will give us a straight line.

This means that this relationship is linear.

The equation y=mx has a graph which has a line with a positive slope that passes through the origin where y is proportional to x and the proportion constant would be m.