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Aluminum oxide (Al2O3) is produced according to the following equation.
4 Al(s) + 3 O2(g) → 2 Al2O3(s)
If the reaction occurs with an 82.4% yield, what mass of aluminum should be reacted with excess oxygen to produce 45.0 grams of Al2O3?
a. 54.6 g Al
b. 37.9 g Al
c. 35.1 g Al
d. 23.8 g Al
e. 28.9 g Al
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