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0.0050 mol of gas undergoes the process 1†’ 2 †’ 3 shown in Figure P16.38.
p (atm) P2 - T = 2926 K 3 T3 = 2438 K 1 0+ V (cm³) V3 FIGURE P16.38 100 200 300
What are
(a) Temperature T1,
(b) Pressure p2,
(c) Volume V3?
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