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Sodium carbonate, Na2CO3, reacts with hydrochloric acid, HCl, to produce sodium chloride, carbon dioxide and water. Refer to slide 7.18 for a summary of formulae relevant to the calculations below. 2HCl(aq) + Na.CO3(aq) + NaCl(aq) + H2O(l) + CO2(g) 1. Use this reaction to explain what is meant by the terms "acid", "conjugate base" and "salt" 2. Balance the equation for this reaction. 3. A solution was prepared by dissolving 5.00 g of Na2CO3 in water and adding water to give 250 mL of solution. Calculate the amount concentration (molarity) of that solution. The Na2CO3 solution described above was used to analyse a hydrochloric acid solution of unknown concentration. It was found that 24.30 mL of the Na-CO3 solution was required to neutralise a 20.00 mL sample of the hydrochloric acid solution. 4. Using your answer to part 3 above, calculate the amount of Na,Co, present in 24.30 mL of the Na2CO: solution. 5. Using your answer to part 2 above, deduce the amount of HCl that was present in the 20.00 mL sample of the HCl solution. 6. Using your answer to part 5 above, calculate the amount concentration of the HCl solution. 7. Assuming that 1 mol of CO2 occupies 24.1 L at room temperature and pressure (i.e. that the molar volume is 24.1 L mol), calculate the volume of CO, formed in this reaction. 8. Calculate the pH of the HCl solution. 9. Strictly speaking, it is not correct to say that the solutions described above contain HCl or Na,CO3. Explain why, specifying what species are actually present in these solutions.
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