I would like you to write two lab reports about two different experiments. I will upload you the instructions on how does the report have to be done. Also, I will upload you the experiment file ( this file will contain everything data, question and answers, purpose, etc..) I would like you to rewrite this answers I wrote on your own words. I will also upload you a sample for an old lab report. I want two pages for each experiment four in total. Thank you!
Final Report
Exercise 1
CHEM 182 DL1 Equilibrium and Le Châtelier’s Principle
Copyright 2019 - Hands-On Labs | http://holscience.com 2 / 6
T he Reaction is Endothermic because the substance became more acidic which equals to higher heat energy.
1. Use your results to determine if the forward reaction in the potassium chromate/HCl reaction endothermic or exothermic. Explain your answer, using the table below to help construct your thoughts.
K=(Cr2 O7)(H20)(KCl)2 / (K2 CrO4) (HCL)2
2. Write the equation for the equilibrium constant (K) of the reaction studied in this exercise.
Copyright 2019 - Hands-On Labs | http://holscience.com 3 / 6
Data Table 1: Chromate and Dichromate
Q=1.6 * 10 (-10 exponent)
Use this information to answer Questions 3, 4, and 5:
The equilibrium constant (K) of the reaction below is K = 6.0 x 10 , with initial concentrations as follows:
[H ] = 1.0 x 10 M, [N ] = 4.0 M, and [NH ] = 1.0 x 10 M.
3. Consider the chemical reaction: N + 3H yields 2NH . If the concentration of the reactant H was increased f rom 1.0 x 10 M to 2.5 x 10 M, calculate the reaction quotient (Q) and determine which way the chemical system would shif t by comparing the value of Q to K.
-2
2 -2 2 3 -4
2 2 3 2 -2 -1
Q=1.270131585632272 * 10 (2 exponent) It will shif t lef t.
4. If the concentration of the reactant H was decreased f rom 1.0 x 10 M to 2.7 x 10 M, calculate the reaction quotient (Q) and determine which way the chemical system would shif t by comparing the value of Q to K.
2 -2 -4
Q=7.84 * 10(-4 exponent). It will shif t right.
5. If the concentration of the product NH was increased f rom 1.0 x 10 M to 5.6 x 10 M, calculate the reaction quotient (Q) and determine which way the chemical system would shif t by comparing the value of Q to K.
3 -4 -3
Copyright 2019 - Hands-On Labs | http://holscience.com 4 / 6
Data Table 2: Endothermic & Exothermic Equilibrium Position
Color of Chromate Color of Dichromate
Color of Chromate Number of Drops of NaOH to Shift Equilibrium Position
Dark yellow Orange
Dark yellow 7
Copyright 2019 - Hands-On Labs | http://holscience.com 5 / 6
Exercise 2
Reaction at Room Temperature
Color
Chemical System Shift (Left or Right)
Explanation of why chemical system is shifted to the left or to the right
Reaction in Cold Water Bath
Color
Chemical System Shift (Left or Right)
Explanation of why chemical system is shifted to the left or to the right
Reaction in Hot Water Bath
Color
Chemical System Shift (Left or Right)
Explanation of why chemical system is shifted to the left or to the right
Red Orange
Bright Orange
Left- towards the reactants
There were solid particles on the bottom of the pipet while the liquid maintained the majority of the pipet. So there was a solid potion and liquid potion. potion.
Red-Orange
Right-Towards the products
The solution was all liquid, so there were no solid particles. This means the reactants mixed together formed the product.
Copyright 2019 - Hands-On Labs | http://holscience.com 6 / 6
Data Table 3: Ferric Ferrocyanide
The equilibrium position would shift left because the product ratio increases when NaOH is added.
1. From your observations and data collected in Data Table 3, describe the direction of the equilibrium posit ion shif t upon addit ion of NaOH.
Color of Potassium Ferrocyanide Color of Ferric Ferrocyanide
Color of Potassium Ferrocyanide
Number of Drops of NaOH to Shift Equilibrium Position
Color of Potassium Ferrocyanide
Observations when Equilibrium is Shifted
Light yellow Dark blue/greenish
Light yellow 4 drops
Light yellow The dark blue/greenish substance turned brown while the surrounding substance turned yellow.