Loading...

Messages

Proposals

Stuck in your homework and missing deadline? Get urgent help in $10/Page with 24 hours deadline

Get Urgent Writing Help In Your Essays, Assignments, Homeworks, Dissertation, Thesis Or Coursework & Achieve A+ Grades.

Privacy Guaranteed - 100% Plagiarism Free Writing - Free Turnitin Report - Professional And Experienced Writers - 24/7 Online Support

Naoac hoac

19/03/2021 Client: saad24vbs Deadline: 24 Hours

Q1:

A] if you are given sodium salt of acetate as ( H3COONa.3H2O, then

1 Molarity = 1 Moles/ 1 litre = 136.09g/ 1 litre [ since 1 mole = 136.09g for CH3COONa.3H2O]

But if we want to make 0.2M Solution of CH3COONa.3H2O, then

0.2M = 0.2*136.09g/L = 27.22g/L or 2.722g/100ml Thus 2.722g of this salt is needed in 100 ml H2O to make its 0.2 solution.

If you are given acetic acid of = 17.47 Molar (liquid), then using molarity equation, M1V1=M2V2

0.2*litre = 17.47*v2

V2 = 0.0114 Litre = 11.4ml of CH3COOH needed in 1 litre H2Oon 1.14 ml of CH3COOH needed in 100ml H2O for making 0.2M solution.

Now, for making 0.1 Molar buffer solution, add 100ml of each of sodium salt of acetate and acetic acid in beaker. Thus we get 0.1M buffer solution of acetic acid and its sodium salt.

B] If now we add a small amount of HCl to above prepared buffer, then sodium salt of acetic acid starts working as

HCl + CH3COONa CH3COOH + NaCl (Weak acid less contribution for H+, formation)

So acid will increase, but it will be very small due to weak dissociation of CH3COOH.

C] If we add small NaOH to buffer solution, then CH3COOH prepared in buffer solution starts working, and forming weak base as

NaOH + CH3COOH CH3COO + Na + H2O (weak base)

So, basicity increases very-small. i.e. reaction is not formable to increase significant basicity.

Q2:

We will prepare a buffer that 1:1 molar ratio of HOAc:NaOAc

[0.1M HOAc + 0.1M NaOAc] ------- combination is a buffer.

HOAc is acetic acid, is a liquid weak acid. Our target concentration is 0.1 M (M stands for molarity = moles / liter)

acetic acid molar mass = 60.05 g/mol

Mass of acetic acid required to prepare 100 mL of 0.1M concentration = [molarity x molar mass of acetic acid] x [volume in mL /1000]

Mass of acetic acid required to prepare 100 mL of 0.1M concentration = [0.1M x 60.05 g/mol] x [100 mL/1000]

Mass of acetic acid required to prepare 100 mL of 0.1M concentration = 0.6005 g, but acetic acid exists as liquid, hence we need to convert mass in grams to volume in mL considering its density.

acetic acid density = 1.049 g/mL, density = mass / volume

volume = mass / density = 0.6005 g / 1.049 g/mL = 0.57 mL

volume of acetic acid has to be taken = 0.57 mL

{Sodium acetate) NaOAc molar mass = 82.0343 g/mol

Mass of sodium acetate required to prepare 100 mL of 0.1M concentration = [0.1M x 82.0343 g/mol] x [100 mL/1000]

Mass of sodium acetate required to prepare 100 mL of 0.1M concentration = 0.82 g

Procedure:

1. Take clean and dry 100 mL graduated volumetric flask with stopper

2. add 0.57 mL of acetic acid to above flask by using graduated 1 mL glass syringe.

3. Now also add 0.82 g of NaOAc to above flask.

4. add pure distilled water to above flask upto the 100 mL mark.

5. Put the glass lid. Now shake well and gently the mixture to get clear homogeneous solution.

6. HOAc-NaOAc buffer solution is prepared

Q3:

If you have equal amount of weak acid and its conjugate base in a buffer, the pH is always = pKa where Ka is the dissociation constant of weak acid. Here Ka = 1.8X10^-5.

So pKa = -log(Ka) = 4.745.

We would use the Henderson-Hasselbalch Equation: pH = pKa + log (base/acid) for acetic acid, let us assume 1.00 M in acetic acid and 1.00 M in sodium acetate pH = 4.745 + log (1.00/1.00) pH = 4.745 + zero pH = 4.745 The same result would happen no matter what the two concentrations were.

Q4:

Given; ka = [H+][oAC-]/[HOAc]

= [H+] = ka[HOAc]/[OAc-]

= ph = Pka + log [(b/vi)/(a/vi)]

= pih = pka + log [b/a] formula for ph of buffer (1)

now X moles of acid is added. So, moles of acid = (a+x) finally

Phb = pka + log (b/(a+x)) (2)

ph = 2-1 = log (b/(a+x)) – log (b/a)

-0.1 = log (a/a+x)

Hp= 2-1 will be negative because we are adding acid so, pH will decrease

X = 0.259a 1M*Vtotal = 0.259

Xmole = 1M * (100ml + V)

A= 1M*100 = 100m mol

X = 0.259

(100+V)ml = 0.259 * 100m mol

V = 59ml

Homework is Completed By:

Writer Writer Name Amount Client Comments & Rating
Instant Homework Helper

ONLINE

Instant Homework Helper

$36

She helped me in last minute in a very reasonable price. She is a lifesaver, I got A+ grade in my homework, I will surely hire her again for my next assignments, Thumbs Up!

Order & Get This Solution Within 3 Hours in $25/Page

Custom Original Solution And Get A+ Grades

  • 100% Plagiarism Free
  • Proper APA/MLA/Harvard Referencing
  • Delivery in 3 Hours After Placing Order
  • Free Turnitin Report
  • Unlimited Revisions
  • Privacy Guaranteed

Order & Get This Solution Within 6 Hours in $20/Page

Custom Original Solution And Get A+ Grades

  • 100% Plagiarism Free
  • Proper APA/MLA/Harvard Referencing
  • Delivery in 6 Hours After Placing Order
  • Free Turnitin Report
  • Unlimited Revisions
  • Privacy Guaranteed

Order & Get This Solution Within 12 Hours in $15/Page

Custom Original Solution And Get A+ Grades

  • 100% Plagiarism Free
  • Proper APA/MLA/Harvard Referencing
  • Delivery in 12 Hours After Placing Order
  • Free Turnitin Report
  • Unlimited Revisions
  • Privacy Guaranteed

6 writers have sent their proposals to do this homework:

Premium Solutions
Custom Coursework Service
Engineering Solutions
Assignments Hut
Quality Assignments
Engineering Exam Guru
Writer Writer Name Offer Chat
Premium Solutions

ONLINE

Premium Solutions

I am known as Unrivaled Quality, Written to Standard, providing Plagiarism-free woork, and Always on Time

$25 Chat With Writer
Custom Coursework Service

ONLINE

Custom Coursework Service

I have read your project details. I can do this within your deadline.

$41 Chat With Writer
Engineering Solutions

ONLINE

Engineering Solutions

I am known as Unrivaled Quality, Written to Standard, providing Plagiarism-free woork, and Always on Time

$91 Chat With Writer
Assignments Hut

ONLINE

Assignments Hut

I have read your project details. I can do this within your deadline.

$95 Chat With Writer
Quality Assignments

ONLINE

Quality Assignments

You can award me any time as I am ready to start your project curiously. Waiting for your positive response. Thank you!

$59 Chat With Writer
Engineering Exam Guru

ONLINE

Engineering Exam Guru

I have read and understood all your initial requirements, and I am very professional in this task.

$64 Chat With Writer

Let our expert academic writers to help you in achieving a+ grades in your homework, assignment, quiz or exam.

Similar Homework Questions

Business Finance Assignment - Kangaroo island ferry costs - Mantra To Control Girlfriend/ Boyfriend +91-9829644411 in france - The future of nursing institute of medicine - Penny from heaven chapter summary - Ccms helpdesk contact number - Sermon on the Mount Group Assignment - Signature Assignment - Leader Interview and Synthesis - Alaska airlines human resources department - I am in blood stepped so far - Project scope for office relocation - Essay - City of casey office - Week 7 - Diagram of a toy car - Keystone personal color test - Intelligent Systems Implementation Process - Gu health waiting periods - System Development Life Cycle: Phases IV & V – Implementation and Maintenance - This is america rhetorical analysis essay - Information Technology Discussion - Dq - La mancha neath christmas menu - British council eal resources - Hexadecimal Calculator - Babylon revisited theme - Virtual lab software engineering - Internal cache content provider journal - Rand robinson kr 1 - Aspermia is the term used to describe - Emergent properties of a cell - MGT312T Week 2 Discussion - Nellie newton applies a force of 50n - Miles converted into kilometers - A medieval life cecilia penifader of brigstock - Divorce lawyer in lahore - Acara year 2 maths - Brigance assessment report example - M11 x 1.5 tap drill size - Urban outfitters social responsibility - Assignment 1 - Problems opportunities objectives and constraints matrix - Hand operated can crusher - Design of snubber circuit for thyristor - Vapor pressure of water at 20 c in mmhg - Interturbine aviation logistics fze - Csu stanislaus student email - Peer response - Marketing management orientation concept - 26 electrons 26 protons - Reading Reflection - Cabinet timbers port melbourne - Neighbor song aunt martha chords - Parrot mki9100 wiring diagram - Badaracco questions of character pdf - Which of the following is a tool that can be used to check for modified or trojanzied files? - Case Study - SPSS Follow Up to a previous assignment - Biological species concept advantages and disadvantages - Sap solution manager test suite training - Iron iii hydroxide plus phosphoric acid - Nursing - Coefficient of restitution theory - The income approach measures gdp by summing - Blue eyes brown eyes experiment - Organizations benefits - Fake facebook powerpoint template - Classification of non verbal communication - Position paper 2.0 - Ec domain in sdtm - Data Science and Big Data - Letter from birmingham jail rhetorical precis - Timberland case study answers - Plan symbols and abbreviations - Specific gas constant steam - Free nursing case studies with answers - Jointcommission org standards_information npsgs aspx - Data table 1 microscope components - How manufacturing organizations use activity-based costing to increase profitability. A minimum of ten scholarly reviewed sources is required. - Rough Draft - Workplace transport safety checklist - Technical description for a non specialized audience - Faust part 1 and 2 - Food chain worksheet pdf - Discussion - St johns river shipyards welding machine is 15 years old - Correct modifiers and concise wording quizlet - Visio context diagram examples - Six key functions that all businesses need to address - What is 2n factorial - Btec engineering level 3 assignments answers - How to find center of circle with endpoints of diameter - Hilux brake controller wiring - Cancer graphic organizer - Hrm 300 total rewards plan worksheet - The forest city - Arlene is to walk across a highwire - The criminal justice system crossword - Technical communication 11th edition pdf free - Disaster Management